Optimal. Leaf size=117 \[ \frac{3 a^3 \cos ^5(c+d x)}{5 d}-\frac{4 a^3 \cos ^3(c+d x)}{3 d}-\frac{a^3 \sin ^3(c+d x) \cos ^3(c+d x)}{6 d}-\frac{7 a^3 \sin (c+d x) \cos ^3(c+d x)}{8 d}+\frac{7 a^3 \sin (c+d x) \cos (c+d x)}{16 d}+\frac{7 a^3 x}{16} \]
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Rubi [A] time = 0.181315, antiderivative size = 133, normalized size of antiderivative = 1.14, number of steps used = 6, number of rules used = 5, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.185, Rules used = {2860, 2678, 2669, 2635, 8} \[ -\frac{7 a^3 \cos ^3(c+d x)}{24 d}-\frac{7 \cos ^3(c+d x) \left (a^3 \sin (c+d x)+a^3\right )}{40 d}+\frac{7 a^3 \sin (c+d x) \cos (c+d x)}{16 d}+\frac{7 a^3 x}{16}-\frac{a \cos ^3(c+d x) (a \sin (c+d x)+a)^2}{10 d}-\frac{\cos ^3(c+d x) (a \sin (c+d x)+a)^3}{6 d} \]
Antiderivative was successfully verified.
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Rule 2860
Rule 2678
Rule 2669
Rule 2635
Rule 8
Rubi steps
\begin{align*} \int \cos ^2(c+d x) \sin (c+d x) (a+a \sin (c+d x))^3 \, dx &=-\frac{\cos ^3(c+d x) (a+a \sin (c+d x))^3}{6 d}+\frac{1}{2} \int \cos ^2(c+d x) (a+a \sin (c+d x))^3 \, dx\\ &=-\frac{a \cos ^3(c+d x) (a+a \sin (c+d x))^2}{10 d}-\frac{\cos ^3(c+d x) (a+a \sin (c+d x))^3}{6 d}+\frac{1}{10} (7 a) \int \cos ^2(c+d x) (a+a \sin (c+d x))^2 \, dx\\ &=-\frac{a \cos ^3(c+d x) (a+a \sin (c+d x))^2}{10 d}-\frac{\cos ^3(c+d x) (a+a \sin (c+d x))^3}{6 d}-\frac{7 \cos ^3(c+d x) \left (a^3+a^3 \sin (c+d x)\right )}{40 d}+\frac{1}{8} \left (7 a^2\right ) \int \cos ^2(c+d x) (a+a \sin (c+d x)) \, dx\\ &=-\frac{7 a^3 \cos ^3(c+d x)}{24 d}-\frac{a \cos ^3(c+d x) (a+a \sin (c+d x))^2}{10 d}-\frac{\cos ^3(c+d x) (a+a \sin (c+d x))^3}{6 d}-\frac{7 \cos ^3(c+d x) \left (a^3+a^3 \sin (c+d x)\right )}{40 d}+\frac{1}{8} \left (7 a^3\right ) \int \cos ^2(c+d x) \, dx\\ &=-\frac{7 a^3 \cos ^3(c+d x)}{24 d}+\frac{7 a^3 \cos (c+d x) \sin (c+d x)}{16 d}-\frac{a \cos ^3(c+d x) (a+a \sin (c+d x))^2}{10 d}-\frac{\cos ^3(c+d x) (a+a \sin (c+d x))^3}{6 d}-\frac{7 \cos ^3(c+d x) \left (a^3+a^3 \sin (c+d x)\right )}{40 d}+\frac{1}{16} \left (7 a^3\right ) \int 1 \, dx\\ &=\frac{7 a^3 x}{16}-\frac{7 a^3 \cos ^3(c+d x)}{24 d}+\frac{7 a^3 \cos (c+d x) \sin (c+d x)}{16 d}-\frac{a \cos ^3(c+d x) (a+a \sin (c+d x))^2}{10 d}-\frac{\cos ^3(c+d x) (a+a \sin (c+d x))^3}{6 d}-\frac{7 \cos ^3(c+d x) \left (a^3+a^3 \sin (c+d x)\right )}{40 d}\\ \end{align*}
Mathematica [A] time = 0.396885, size = 76, normalized size = 0.65 \[ \frac{a^3 (-15 \sin (2 (c+d x))-105 \sin (4 (c+d x))+5 \sin (6 (c+d x))-600 \cos (c+d x)-140 \cos (3 (c+d x))+36 \cos (5 (c+d x))+450 c+420 d x)}{960 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.036, size = 156, normalized size = 1.3 \begin{align*}{\frac{1}{d} \left ({a}^{3} \left ( -{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{6}}-{\frac{ \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sin \left ( dx+c \right ) }{8}}+{\frac{\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{16}}+{\frac{dx}{16}}+{\frac{c}{16}} \right ) +3\,{a}^{3} \left ( -1/5\, \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}-2/15\, \left ( \cos \left ( dx+c \right ) \right ) ^{3} \right ) +3\,{a}^{3} \left ( -1/4\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sin \left ( dx+c \right ) +1/8\,\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) +1/8\,dx+c/8 \right ) -{\frac{{a}^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{3}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.09966, size = 143, normalized size = 1.22 \begin{align*} -\frac{320 \, a^{3} \cos \left (d x + c\right )^{3} - 192 \,{\left (3 \, \cos \left (d x + c\right )^{5} - 5 \, \cos \left (d x + c\right )^{3}\right )} a^{3} + 5 \,{\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} - 12 \, d x - 12 \, c + 3 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{3} - 90 \,{\left (4 \, d x + 4 \, c - \sin \left (4 \, d x + 4 \, c\right )\right )} a^{3}}{960 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.70915, size = 215, normalized size = 1.84 \begin{align*} \frac{144 \, a^{3} \cos \left (d x + c\right )^{5} - 320 \, a^{3} \cos \left (d x + c\right )^{3} + 105 \, a^{3} d x + 5 \,{\left (8 \, a^{3} \cos \left (d x + c\right )^{5} - 50 \, a^{3} \cos \left (d x + c\right )^{3} + 21 \, a^{3} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{240 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 5.61595, size = 328, normalized size = 2.8 \begin{align*} \begin{cases} \frac{a^{3} x \sin ^{6}{\left (c + d x \right )}}{16} + \frac{3 a^{3} x \sin ^{4}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{16} + \frac{3 a^{3} x \sin ^{4}{\left (c + d x \right )}}{8} + \frac{3 a^{3} x \sin ^{2}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{16} + \frac{3 a^{3} x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{4} + \frac{a^{3} x \cos ^{6}{\left (c + d x \right )}}{16} + \frac{3 a^{3} x \cos ^{4}{\left (c + d x \right )}}{8} + \frac{a^{3} \sin ^{5}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{16 d} - \frac{a^{3} \sin ^{3}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{6 d} + \frac{3 a^{3} \sin ^{3}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{8 d} - \frac{a^{3} \sin ^{2}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{d} - \frac{a^{3} \sin{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{16 d} - \frac{3 a^{3} \sin{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{8 d} - \frac{2 a^{3} \cos ^{5}{\left (c + d x \right )}}{5 d} - \frac{a^{3} \cos ^{3}{\left (c + d x \right )}}{3 d} & \text{for}\: d \neq 0 \\x \left (a \sin{\left (c \right )} + a\right )^{3} \sin{\left (c \right )} \cos ^{2}{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.37411, size = 143, normalized size = 1.22 \begin{align*} \frac{7}{16} \, a^{3} x + \frac{3 \, a^{3} \cos \left (5 \, d x + 5 \, c\right )}{80 \, d} - \frac{7 \, a^{3} \cos \left (3 \, d x + 3 \, c\right )}{48 \, d} - \frac{5 \, a^{3} \cos \left (d x + c\right )}{8 \, d} + \frac{a^{3} \sin \left (6 \, d x + 6 \, c\right )}{192 \, d} - \frac{7 \, a^{3} \sin \left (4 \, d x + 4 \, c\right )}{64 \, d} - \frac{a^{3} \sin \left (2 \, d x + 2 \, c\right )}{64 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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